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songdg
V2EX  ›  Python

如何将 1 个数组分割成相隔 1 的多个数组

  •  
  •   songdg · 2018-05-31 13:02:51 +08:00 · 2422 次点击
    这是一个创建于 2128 天前的主题,其中的信息可能已经有所发展或是发生改变。
    array([ 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12,
    13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25,
    26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38,
    39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51,
    52, 69, 72, 73, 74, 75, 76, 77, 86, 97, 98, 100, 101,
    102, 103, 104, 105, 106, 107, 108, 109, 110, 111, 112, 113, 114,
    115, 116, 117, 118, 119, 120, 121, 122, 123, 124, 125, 126, 129,
    130, 131, 142, 143, 144, 145, 146, 147, 148, 149, 150, 151, 152,
    153, 154, 155, 156, 157, 158, 159, 160, 197, 198, 199, 200, 201,
    202, 203, 204, 206, 207, 208, 209, 210, 216, 217, 218, 219, 220,
    221, 222, 223, 224, 225, 226, 227, 228, 229, 230, 231, 232, 233,
    234, 235, 236, 237, 239, 240, 241, 242, 243, 244, 259, 271, 272,
    273, 274, 275, 276, 277, 278, 279, 280, 281, 282, 283, 284, 285,
    286, 287, 288, 289, 290, 291, 292, 293, 294])
    16 条回复    2018-06-03 20:14:42 +08:00
    songdg
        1
    songdg  
    OP
       2018-05-31 15:07:28 +08:00
    我的笨拙方法:
    arr = array([ 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12,
    13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25,
    26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38,
    39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51,
    52, 69, 72, 73, 74, 75, 76, 77, 86, 97, 98, 100, 101,
    102, 103, 104, 105, 106, 107, 108, 109, 110, 111, 112, 113, 114,
    115, 116, 117, 118, 119, 120, 121, 122, 123, 124, 125, 126, 129,
    130, 131, 142, 143, 144, 145, 146, 147, 148, 149, 150, 151, 152,
    153, 154, 155, 156, 157, 158, 159, 160, 197, 198, 199, 200, 201,
    202, 203, 204, 206, 207, 208, 209, 210, 216, 217, 218, 219, 220,
    221, 222, 223, 224, 225, 226, 227, 228, 229, 230, 231, 232, 233,
    234, 235, 236, 237, 239, 240, 241, 242, 243, 244, 259, 271, 272,
    273, 274, 275, 276, 277, 278, 279, 280, 281, 282, 283, 284, 285,
    286, 287, 288, 289, 290, 291, 292, 293, 294])
    brr = np.append(arr,arr[-1] + 1)
    crr = np.where(brr[1:] - arr != 1)
    drr = []
    k = 0
    for i in crr:
    devi.append(arr[k:i])
    k = i
    devi.append(arr[i:])
    epicnoob
        2
    epicnoob  
       2018-05-31 15:26:26 +08:00
    看不懂你的要求,代码也执行不了。
    zzj0311
        3
    zzj0311  
       2018-05-31 16:36:00 +08:00 via Android
    [::2 ]?看不懂代码+1
    songdg
        4
    songdg  
    OP
       2018-05-31 17:06:45 +08:00
    不能修改帖子,只能在这里修改有错的代码:
    arr = array([ 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12,
    13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25,
    26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38,
    39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51,
    52, 69, 72, 73, 74, 75, 76, 77, 86, 97, 98, 100, 101,
    102, 103, 104, 105, 106, 107, 108, 109, 110, 111, 112, 113, 114,
    115, 116, 117, 118, 119, 120, 121, 122, 123, 124, 125, 126, 129,
    130, 131, 142, 143, 144, 145, 146, 147, 148, 149, 150, 151, 152,
    153, 154, 155, 156, 157, 158, 159, 160, 197, 198, 199, 200, 201,
    202, 203, 204, 206, 207, 208, 209, 210, 216, 217, 218, 219, 220,
    221, 222, 223, 224, 225, 226, 227, 228, 229, 230, 231, 232, 233,
    234, 235, 236, 237, 239, 240, 241, 242, 243, 244, 259, 271, 272,
    273, 274, 275, 276, 277, 278, 279, 280, 281, 282, 283, 284, 285,
    286, 287, 288, 289, 290, 291, 292, 293, 294])
    brr = np.append(arr,arr[-1] + 1) #使 brr 为 array([ 0, 1, 2, ......, 293, 294, 295])
    crr = np.where(brr[1:] - arr != 1)
    drr = []
    k = 0
    for i in crr:
    drr.append(arr[k:i])
    k = i
    drr.append(arr[i:])
    swulling
        5
    swulling  
       2018-05-31 18:15:22 +08:00 via iPhone
    你贴示例数组,是不是贴十来个元素就可以了,至于贴这么长的么
    GeruzoniAnsasu
        6
    GeruzoniAnsasu  
       2018-05-31 18:32:23 +08:00
    随意到底是想干嘛都没说清楚?
    songdg
        7
    songdg  
    OP
       2018-05-31 18:45:38 +08:00
    就是数组[ 0, 1, 2, 3, 6, 7, 8, 9, 10, 12, 14, 15, 16, 17, 18, 19, 23, 24, 27, 28, 29, 30]分割成[ 0, 1, 2, 3][6, 7, 8, 9, 10][12][14, 15, 16, 17, 18, 19][23, 24][27, 28, 29, 30]
    whoami9894
        8
    whoami9894  
       2018-05-31 18:48:53 +08:00 via Android
    @songdg 你这分割的长度是依照什么
    wingkou
        9
    wingkou  
       2018-05-31 21:23:43 +08:00 via Android
    @songdg 早说这个不就行了吗,是把大数组分割成元素连续的一个个数组吧?你大数组一定是升序的吗?
    menc
        10
    menc  
       2018-05-31 21:32:48 +08:00
    最简解法只需要一行
    menc
        11
    menc  
       2018-05-31 21:34:59 +08:00   ❤️ 1
    songdg
        12
    songdg  
    OP
       2018-06-01 08:57:50 +08:00
    @menc 非常感谢帮助。
    msg7086
        13
    msg7086  
       2018-06-01 10:09:42 +08:00   ❤️ 1
    无序的话可以用双向头尾哈希表,有序的话直接遍历搜索 arr[i] - arr[i-1] != 1 就行了。
    necomancer
        14
    necomancer  
       2018-06-03 14:25:03 +08:00   ❤️ 1
    In [1]: a = np.array([ 0, 1, 2, 3, 6, 7, 8, 9, 10, 12, 14, 15, 16, 17, 18, 19, 23, 24, 27, 28, 29, 30])

    In [2]: np.split(a,np.argwhere(np.diff(a-np.arange(a.shape[0]))!=0).flatten()+1)
    Out[2]:
    [array([0, 1, 2, 3]),
    array([ 6, 7, 8, 9, 10]),
    array([12]),
    array([14, 15, 16, 17, 18, 19]),
    array([23, 24]),
    array([27, 28, 29, 30])]
    songdg
        15
    songdg  
    OP
       2018-06-03 20:14:31 +08:00
    @msg7086 谢谢帮助。
    songdg
        16
    songdg  
    OP
       2018-06-03 20:14:42 +08:00
    @necomancer @msg7086 谢谢帮助。
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