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madworks
V2EX  ›  Java

报表分组通用 sql 解决方案已出

  •  
  •   madworks · 2020-11-02 10:53:34 +08:00 · 2469 次点击
    这是一个创建于 1508 天前的主题,其中的信息可能已经有所发展或是发生改变。

    接上一主题 https://www.v2ex.com/t/719136

    通过 dba 的苦思冥想,sql 已经出来了,大家有这方面的可以参考下 sql 效果图见下,懂的人已懂

    https://vkceyugu.cdn.bspapp.com/VKCEYUGU-imgbed/9a586ec3-41ea-4190-9b03-37ceb074c486.png

    行分组字段 row1,row2,列分组字段 column1,column2,column1 有 012 三种状态,column2 有 01 两种状态,sql 可以呈现 column1,column2 所有组合的值并小计总计,而且可以随意扩展,sql 也是很简洁,稍微变换下可以解决行的分组,可以完美呈现类似下面的报表

    https://vkceyugu.cdn.bspapp.com/VKCEYUGU-imgbed/0dfbb436-d5b1-493e-b0d9-2918aecd145e.png 不用自己再逻辑处理数据,动态分组处理逻辑代码简直写的崩溃,不信的人可以去试下

    17 条回复    2020-11-02 16:15:09 +08:00
    madworks
        1
    madworks  
    OP
       2020-11-02 10:56:38 +08:00
    建表 sql
    SET FOREIGN_KEY_CHECKS=0;
    DROP TABLE IF EXISTS `xx`;
    CREATE TABLE `xx` (
    `id` int(11) NOT NULL,
    `fee` int(255) DEFAULT NULL,
    `column1` varchar(255) DEFAULT NULL,
    `column2` varchar(255) DEFAULT NULL,
    `row1` varchar(255) DEFAULT NULL,
    `row2` varchar(255) DEFAULT '',
    PRIMARY KEY (`id`)
    ) ENGINE=InnoDB DEFAULT CHARSET=utf8;

    INSERT INTO `xx` VALUES ('1', '454', '0', '1', '李', '湖北');
    INSERT INTO `xx` VALUES ('2', '35', '1', '0', '王', '上海');
    INSERT INTO `xx` VALUES ('3', '23', '1', '1', '李', '上海');
    INSERT INTO `xx` VALUES ('4', '567', '1', '0', '李', '上海');
    INSERT INTO `xx` VALUES ('5', '43', '0', '2', '王', '湖北');
    INSERT INTO `xx` VALUES ('6', '456', '0', '1', '李', '河南');
    zoharSoul
        2
    zoharSoul  
       2020-11-02 10:57:06 +08:00
    听起来就是行转列?
    madworks
        3
    madworks  
    OP
       2020-11-02 10:57:12 +08:00
    实现 sql
    SELECT
    row1,
    row2,
    IFNULL(column1,'总计'),
    IFNULL(column2,'小计'),
    sum(fee) fee
    FROM
    (
    SELECT
    row1,
    row2,
    column1,
    column2,
    fee
    FROM
    (
    SELECT
    *
    FROM
    (
    SELECT
    x.row1,
    x.row2,
    y.column1,
    y.column2,
    0 AS fee
    FROM
    (
    SELECT
    row1,
    row2
    FROM
    xx
    GROUP BY
    row1,
    row2,
    column1,
    column2
    ) x,
    (
    SELECT
    *
    FROM
    (
    SELECT
    0 AS column1
    UNION
    SELECT
    1 AS column1
    ) AS t1
    LEFT JOIN (
    SELECT
    0 AS column2
    UNION
    SELECT
    1 AS column2
    UNION
    SELECT
    2 AS column2
    ) AS t2 ON 1 = 1
    ) y
    WHERE
    (3 * y.column1 + y.column2) NOT IN (
    SELECT
    3 * m.column1 + m.column2
    FROM
    xx m
    WHERE
    m.row1 = x.row1
    AND m.row2 = x.row2
    )
    GROUP BY
    row1,
    row2,
    column1,
    column2
    ) n
    UNION
    SELECT
    row1,
    row2,
    column1,
    column2,
    sum(fee) fee
    FROM
    xx
    GROUP BY
    row1,
    row2,
    column1,
    column2
    ) temp
    GROUP BY
    row1,
    row2,
    column1,
    column2
    ) AS temp
    GROUP BY
    row1,
    row2,
    column1,
    column2 WITH ROLLUP
    madworks
        4
    madworks  
    OP
       2020-11-02 11:00:20 +08:00
    @zoharSoul,不是行转列,有 2 个行,2 个列,每行每列都有固定的几个状态,一些行列组合肯定没有记录,现在写个 sql 可以展现所有组合的值,没有记录的赋值 0,你怎么写?听起来很简单,但是实现起来还是比较难的
    weizhen199
        5
    weizhen199  
       2020-11-02 11:06:53 +08:00
    pivot 应该是可以的

    还有 dba 帮忙写业务 sql 的,太羡慕。。。/哭
    madworks
        6
    madworks  
    OP
       2020-11-02 11:12:16 +08:00
    @weizhen199 是啊,pbi,tableau 这种写这个不要太简单,可惜不开源,不能搞在项目里,只能单独的搭建一套报表系统
    madworks
        7
    madworks  
    OP
       2020-11-02 11:17:47 +08:00
    @weizhen199 @zoharSoul 你们说的好像是一个,我了解下,我以为你说的 bi pivot
    l00t
        8
    l00t  
       2020-11-02 12:05:11 +08:00
    这样不还是存在你在原帖中自己评论的问题?值多了怎么办?打算写多长?

    不如搞个字典表,直接关联上字典表,比你这么挨个 select 要简洁很多。而且字典表也方便管理这种状态值,甚至可以把中文说明都给直接带出来。
    madworks
        9
    madworks  
    OP
       2020-11-02 13:53:14 +08:00
    @l00t 哈哈,是这样的,多谢
    madworks
        10
    madworks  
    OP
       2020-11-02 14:25:54 +08:00
    SELECT
    row1,
    row2,
    IFNULL(column1, '总计'),
    IFNULL(column2, '小计'),
    sum(fee) fee
    FROM
    (
    SELECT
    row1,
    row2,
    column1,
    column2,
    fee
    FROM
    (
    SELECT
    *
    FROM
    (
    SELECT
    x.row1,
    x.row2,
    y.column1,
    y.column2,
    0 AS fee
    FROM
    (
    SELECT
    row1,
    row2
    FROM
    xx_index
    GROUP BY
    row1,
    row2
    ) x,
    (
    SELECT
    column1,
    column2
    FROM
    xx_index
    GROUP BY
    column1,
    column2
    ) y
    WHERE
    (3 * y.column1 + y.column2) NOT IN (
    SELECT
    3 * m.column1 + m.column2
    FROM
    xx m
    WHERE
    m.row1 = x.row1
    AND m.row2 = x.row2
    )
    GROUP BY
    row1,
    row2,
    column1,
    column2
    ) n
    UNION
    SELECT
    row1,
    row2,
    column1,
    column2,
    sum(fee) fee
    FROM
    xx
    GROUP BY
    row1,
    row2,
    column1,
    column2
    ) temp
    GROUP BY
    row1,
    row2,
    column1,
    column2
    ) AS temp
    GROUP BY
    row1,
    row2,
    column1,
    column2 WITH ROLLUP
    wysnylc
        11
    wysnylc  
       2020-11-02 14:29:54 +08:00
    代码可能不会超过 10 行(lambda)
    madworks
        12
    madworks  
    OP
       2020-11-02 14:43:32 +08:00
    @wysnylc 太自信了
    zifangsky
        13
    zifangsky  
       2020-11-02 15:29:14 +08:00
    你这个 SQL 写得也太复杂了吧,先不说在数据量大的情况下执行速度怎么样,光是后期维护也非常困难吧。而且,一般来说复杂逻辑都是放在业务代码里手动实现,SQL 只做简单高效的查询就可以了
    madworks
        14
    madworks  
    OP
       2020-11-02 16:04:59 +08:00
    @zifangsky 这 sql 只是看起来长,不复杂啊,修改的话就套模板,很快的。执行速度的话只要行列分组不超过 5 个都在 1 分钟之类,这种报表用逻辑代码写才是噩梦,我写出来要几百行代码,各种递归,小计总计还要判断位置,没写过想象不到的复杂
    madworks
        15
    madworks  
    OP
       2020-11-02 16:10:32 +08:00
    @zifangsky 随便给你看下插入小计的位置的代码
    public void getInsertPosition(int levelFlag, List<List<Integer>> groupOrderInfoNumCollection,
    List<OrderInfo> orderInfoList, int len, List<List<Integer>> nodeIndexList, List<List<Integer>> nestOrderInfoRepeatCollection)
    {
    int insertPos = 0;
    int position = 0;
    int[] listLen = new int[levelFlag];

    if (levelFlag >= 1)
    {
    int[] index = new int[levelFlag];
    for (int i = 0; i < levelFlag - 1; i++)
    {
    index[i] = groupOrderInfoNumCollection.get(i + 1).get(0);
    }
    for (Integer integer : groupOrderInfoNumCollection.get(0))
    {
    position += len * integer;
    orderInfoList.remove(position);
    insertPos += integer;
    nodeIndexList.get(0).add(insertPos);
    if(integer == 1){
    nestOrderInfoRepeatCollection.get(0).add(insertPos);
    }
    for (int i = 0; i < levelFlag - 1; i++)
    {
    if (insertPos == index[i])
    {
    nodeIndexList.get(i + 1).add(insertPos);
    orderInfoList.remove(insertPos * len);
    listLen[i]++;
    if (listLen[i] < groupOrderInfoNumCollection.get(i + 1).size())
    {
    index[i] += groupOrderInfoNumCollection.get(i + 1).get(listLen[i]);
    }
    }
    }
    }
    if(orderInfoList.size() > 1){
    orderInfoList.remove(orderInfoList.size() - 1);
    }
    }
    }
    madworks
        16
    madworks  
    OP
       2020-11-02 16:14:26 +08:00
    把结果集整理成需要的形式的代码
    public void resultSetHandler(int rowLen, int levelFlag, Map<String, Object> map,
    Map<String, Object> rowGroupMap, String[] rowParamArr,
    List<List<OrderInfo>> nestOrderInfoCollection, int len, int i)
    {
    if (rowLen >= 1)
    {
    List<List<Integer>> temp = new ArrayList<>();
    levelFlag--;
    map.remove(rowParamArr[rowLen]);
    rowGroupMap.remove(rowParamArr[rowLen]);
    nestOrderInfoCollection.get(i).addAll(performanceService.getOrderInfo(map));
    deleteNodeTotal(nestOrderInfoCollection.get(i), len, rowGroupMap, rowParamArr, levelFlag,temp,temp);
    rowLen--;
    i++;
    resultSetHandler(rowLen, levelFlag, map, rowGroupMap, rowParamArr, nestOrderInfoCollection, len, i);
    }
    }
    madworks
        17
    madworks  
    OP
       2020-11-02 16:15:09 +08:00
    删除节点统计的代码
    public void deleteNodeTotal(List<OrderInfo> orderInfoList, int len,
    Map<String, Object> rowGroupMap, String[] rowParamArr, int levelFlag, List<List<Integer>> nestOrderInfoIndexCollection, List<List<Integer>> nestOrderInfoRepeatCollection)
    {

    List<List<Integer>> groupOrderInfoNumCollection = new ArrayList<List<Integer>>();
    for (int i = 0; i < levelFlag; i++)
    {
    nestOrderInfoIndexCollection.add(new ArrayList<Integer>());
    nestOrderInfoRepeatCollection.add(new ArrayList<Integer>());
    groupOrderInfoNumCollection.add(new ArrayList<Integer>());
    }

    if (rowParamArr.length > 1)
    {

    getGroupOrderInfoNum(levelFlag, rowGroupMap, rowParamArr, groupOrderInfoNumCollection);

    if (levelFlag >= 1)
    {
    getInsertPosition(levelFlag, groupOrderInfoNumCollection, orderInfoList, len, nestOrderInfoIndexCollection, nestOrderInfoRepeatCollection);
    }
    }

    }
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