大家好 请教一个 redis lua 脚本问题

[gosansam]

调用 tonumber 函数后都是 nil ，直接 return tonumber(ARGV[2])也是 null ，但是下面的返回 ARGV[2]返回是字符串 2 ，在 redis 客户端执行 eval "return tonumber(ARGV[1])" 1, 1, 2 可以返回 2 ，请问是为啥呢？

    @Test
    void testSc() {
        String s =
                "local first = tonumber(ARGV[1]) " +
                        "local second = tonumber(ARGV[2]) " +
                        "local third = tonumber(ARGV[3]) " +
                        "local fourth= tonumber(ARGV[4]) " +
//                "return tonumber(ARGV[2])";	//返回 null
                        "return second";	//返回 null
        DefaultRedisScript<Long> script = new DefaultRedisScript<>();
        script.setScriptText(s);
        script.setResultType(Long.class);
        Long executeTimes = redisTemplate.execute(script, Collections.singletonList("key"), 1 + "", 2 + "",
                3 + "", 4 + "");
        System.out.println("tonumber: " + executeTimes);

        s =
                "local first = tonumber(ARGV[1]) " +
                        "local second = tonumber(ARGV[2]) " +
                        "local third = tonumber(ARGV[3]) " +
                        "local fourth= tonumber(ARGV[4]) " +
                        "return ARGV[4] ";	//返回 4
        DefaultRedisScript<String> redisScript = new DefaultRedisScript<>();
        redisScript.setScriptText(s);
        redisScript.setResultType(String.class);
        String res = redisTemplate.execute(redisScript, Collections.singletonList("key"), 1 + "", 2 + "",
                3 + "", 4 + "");
        System.out.println("string: " + res);
    }

不知道怎么解决了。。脚本不用 local 声明变量，入参用 Object 数组放 long 数值可以了

[Yoock]

https://redis.io/docs/manual/programmability/lua-debugging/