获取到 4 位数中能被 3 整除不能被 6 整除的数
list = filter(None, [i if(i%3 is 0 and i%6 is not 0) else None for i in range(1000, 10000)])

写一个返回指定长度并从元列表中剔除这些元素的方法
def push_num(list, reqlen):
count = 0
req = []
while count is not reqlen:
req.append(list[0])
del list[0]
count += 1
return req

再写一个交替判断
def list_slice(list):
req = []
req.append(push_num(list, 2))
while True:
if len(list) is 0:
return req
if len(req[-1]) is 3:
req.append(push_num(list, 2))
elif len(req[-1]) is 2:
req.append(push_num(list, 3))

最后 结合一下
list_slice( filter(None, [i if(i%3 is 0 and i%6 is not 0) else None for i in range(1000, 10000)]) )